SATHEE: Relations Question 27

Relations Question 27

Question: Let $ f(x)=\frac{ax}{x+1}, $ $ x\ne -1 $ . Then, the value of $ \alpha >0 $ for which $ f[f(x)]=x $ is

Solution:

Answer: 1

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Relations Question 27

Question: Let $ f(x)=\frac{ax}{x+1}, $ $ x\ne -1 $ . Then, the value of $ \alpha >0 $ for which $ f[f(x)]=x $ is

Solution:

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