SATHEE: Relations Question 48

Relations Question 48

Question: Let $ f(x)=ax^{2}+bx+c, $ $ g(x)=px^{2}+qx+r, $ such that $ f(1)=g(1), $ $ f(2)=g(2) $ and $ f(3)-g(3)=2. $ Then $ f(4)-g(4) $ is

Solution:

Answer: 6

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Relations Question 48

Question: Let $ f(x)=ax^{2}+bx+c, $ $ g(x)=px^{2}+qx+r, $ such that $ f(1)=g(1), $ $ f(2)=g(2) $ and $ f(3)-g(3)=2. $ Then $ f(4)-g(4) $ is

Solution:

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