Sequence And Series Question 102
Question: $ \frac{1}{2}+\frac{1}{4}+\frac{1}{8(2),!}+\frac{1}{16,(3),!}+\frac{1}{32(4),!}+……\infty = $
Options:
A) $ e $
B) $ \sqrt{e} $
C) $ \frac{\sqrt{e}}{2} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ S=\frac{1}{2}{ 1+\frac{( \frac{1}{2} )}{1!}+\frac{{{( \frac{1}{2} )}^{n}}}{2!}+…. }=\frac{1}{2}{e^{1/2}}=\frac{\sqrt{e}}{2} $ .
BETA
