Sequence And Series Question 11
Question: The 4th term of a H.P. is $ \frac{3}{5} $ and 8th term is $ \frac{1}{3}, $ then its 6th term is
[MP PET 2003]
Options:
A) $ \frac{1}{6} $
B) $ \frac{3}{7} $
C) $ \frac{1}{7} $
D) $ \frac{3}{5} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ a+3d=\frac{5}{3} $ and $ a+7d=3 $ Solving, $ a=\frac{2}{3},d=\frac{1}{3} $ 6th term of A.P. $ =a+5d=\frac{2}{3}+\frac{5}{3}=\frac{7}{3} $
Þ 6th term of H.P. = $ \frac{3}{7} $ .
BETA
