[MP PET 1991]
A) $ {e^{-1}} $
B) $ e $
C) $ \frac{e+{e^{-1}}}{2} $
D) $ \frac{e-{e^{-1}}}{2} $
Correct Answer: D
$ 1+\frac{1}{3\ !}+\frac{1}{5\ !}+\frac{1}{7\ !}+……\infty =\frac{e-{e^{-1}}}{2} $ .
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