Sequence And Series Question 123
Question: If the numbers $ a,\ b,\ c,\ d,\ e $ form an A.P., then the value of $ a-4b+6c-4d+e $ is
Options:
A) 1
B) 2
C) 0
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Let $ D $ be the common difference of the A.P. Then, $ a-4b+6c-4d+e= $ $ a-4(a+D)+6(a+2D)-4(a+3D)+(a+4D)=0 $ .
BETA
