[RPET 1995]
A) $ \frac{m(m+1)}{2} $
B) $ \frac{m(m+1)(2m+1)}{6} $
C) $ \frac{n(n+1)(2n+1)}{6} $
D) $ \frac{n(n+1)}{2} $
Correct Answer: C
It is nothing but $ {S_{\infty }}=\frac{a}{1-r}=\frac{\sqrt{2}+1}{1-(\sqrt{2}-1)} $ .
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