Sequence And Series Question 163
Question: The nth term of the series $ \frac{2}{1!}+\frac{7}{2,!}+\frac{15}{3,!}+\frac{26}{4,!}+….. $ is
Options:
A) $ \frac{n,(3n-1)}{2(n),!} $
B) $ \frac{n,(3n+1)}{2,(n),!} $
C) $ \frac{n}{2}\frac{3n}{(n),!} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
The series is $ \frac{2}{1!}+\frac{(2+5)}{2!}+\frac{( 2+5+8 )}{3!}+\frac{(2+5+8+11)}{4!}+…. $ Hence $ T_{n}=\frac{(2+5+8+……n,terms)}{n!}=\frac{\frac{n}{2}[2.2+(n-1)3]}{n!} $ $ T_{n}=\frac{n,(3n+1)}{2(n)!} $ .
BETA
