Sequence And Series Question 17
Question: In the expansion of $ \frac{e^{4x}-1}{e^{2x}} $ , the coefficient of $ x^{2} $ is
Options:
A) $ \frac{1}{2} $
1
0
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{e^{4x}-1}{e^{2x}}=e^{2x}-{e^{-2x}}=2{ x+\frac{{{(2x)}^{3}}}{3\ !}+\frac{{{(2x)}^{5}}}{5\ !}+….. } $ The coefficient of $ x^{2}=0 $ .
BETA
