Sequence And Series Question 228
Question: If G.M. = 18 and A.M. = 27, then H.M. is
[RPET 1996]
Options:
A) $ \frac{1}{18} $
B) $ \frac{1}{12} $
C) 12
D) $ 9\sqrt{6} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \because $ $ G^{2}=AH $
$ \Rightarrow $ $ {{(18)}^{2}}=27H $
$ \Rightarrow $ $ H=12 $ .