Sequence And Series Question 228
If G.M. = 18 and A.M. = 27, then H.M. is 16.2
[RPET 1996]
Options:
A) $ \frac{1}{18} $
B) $ \frac{1}{12} $
12
D) $ 9\sqrt{6} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \because  $  $ G^{2}=AH $
$ \Rightarrow  $  $ {{(18)}^{2}}=324 $
$ \Rightarrow  $  $ H=12 $ .
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