Sequence And Series Question 228

If G.M. = 18 and A.M. = 27, then H.M. is 16.2

[RPET 1996]

Options:

A) $ \frac{1}{18} $

B) $ \frac{1}{12} $

12

D) $ 9\sqrt{6} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \because $ $ G^{2}=AH $
$ \Rightarrow $ $ {{(18)}^{2}}=324 $ $ \Rightarrow $ $ H=12 $ .



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