Sequence And Series Question 264
Question: If $ a,\ b,\ c $ are in A.P. and $ a,\ c-b,\ b-a $ are in G.P. $ (a\ne b\ne c) $ , then $ a:b:c $ is
Options:
A) $ 1:3:5 $
B) $ 1:2:4 $
C) $ 1:2:3 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Check by options (a) 1, 3, 5 are in A.P. but 1, 5 - 3, 3 - 1 $ i.e. $ , 1, 2, 2 are not in G.P. (b) 1, 2, 4 are not in A.P. (c) 1, 2, 3 are in A.P. and 1, $ 3\ -2,\ 2-1\ i.e.,\ $ 1, 1, 1 are also in G.P.
BETA
