Sequence And Series Question 279
Question: Three numbers are in A.P. whose sum is 33 and product is 792, then the smallest number from these numbers is
[RPET 1988]
Options:
A) 4
B) 8
C) 11
D) 14
Show Answer
Answer:
Correct Answer: A
Solution:
Suppose that three numbers are $ a+d,\ a,\ a-d, $ therefore $ a+d+a+a-d=33 $
$ \Rightarrow $ $ a=11 $ $ a(a+d)(a-d)=792 $
$ \Rightarrow $ $ 11(121-d^{2})=792 $
$ \Rightarrow $ $ d=7 $ Then required numbers are 4, 11, 18. Hence smallest number is 4.
BETA
