Sequence And Series Question 33
Question: The $ 9^{th} $ term of the series $ 27+9+5\frac{2}{5}+3\frac{6}{7}+…….. $ will be
[MP PET 1983]
Options:
A) $ 1\frac{10}{17} $
B) $ \frac{10}{17} $
C) $ \frac{16}{27} $
D) $ \frac{17}{27} $
Show Answer
Answer:
Correct Answer: A
Solution:
Given series $ 27+9+5\ .\ \frac{2}{5}+3\ .\ \frac{6}{7}+…… $ $ =27+\frac{27}{3}+\frac{27}{5}+\frac{27}{7}+…..+\frac{27}{2n-1}+…… $ Hence $ n^{th} $ term of given series $ T_{n}=\frac{27}{2n-1} $ So, $ T_9=\frac{27}{2\times 9-1}=\frac{27}{17}=1\frac{10}{17} $ .
BETA
