Sequence And Series Question 332
Question: The ratio of the sums of first $ n $ even numbers and $ n $ odd numbers will be
Options:
A) $ 1:n $
B) $ (n+1):1 $
C) $ (n+1):n $
D) $ (n-1):1 $
Show Answer
Answer:
Correct Answer: C
Solution:
Let $ S_{Even}=2+4+6+8+……..\infty $ ?..(i) and $ S_{Odd}=1+3+5+7+9+…….\infty $ ?..(ii) Sum $ c $ and $ S_{O}=\frac{n}{2}[2+(n-1)2]=\frac{n}{2}(2n) $ Now $ \frac{S_{E}}{S_{O}}=\frac{(n+1)}{n} $ or $ S_{E}:S_{O}=(n+1):n $ .
BETA
