Sequence And Series Question 386
Question: If a, b, c are in GP., then
Options:
A) $ a^{2},b^{2},c^{2} $ are in GP.
B) $ a^{2}(b+c),c^{2}(a+b),b^{2}(a+c) $ are in G.P.
C) $ \frac{a}{b+c},\frac{b}{c+a},\frac{c}{a+b} $ are in G.P.
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ \because $ a, b, c are in GP.
$ \therefore \frac{b}{a}=\frac{c}{b}=r\Rightarrow \frac{b^{2}}{a^{2}}=\frac{c^{2}}{b^{2}}=r^{2} $
$ \Rightarrow a^{2},{b^{2,}}c^{2} $ are in GP.
BETA
