Sequence And Series Question 402
Question: $ 1+\frac{3}{1,!}+\frac{5}{2,!}+\frac{7}{3,!}+….\infty = $
Options:
A) $ e $
B) $ 2,e $
C) $ 3,e $
D) $ 4,e $
Show Answer
Answer:
Correct Answer: C
Solution:
$ 1+\frac{3}{1!}+\frac{5}{2!}+\frac{7}{3!}+….\infty $ $ T_{n}=\frac{2n-1}{(n-1)!}=\frac{2(n-1)}{(n-1)!}+\frac{1}{(n-1)!} $ $ =\frac{2}{(n-2)!}+\frac{1}{(n-1)!}=2e+e=3e $ .
BETA
