Sequence And Series Question 408
Question: The A.M., H.M. and G.M. between two numbers are $ \frac{144}{15} $ , 15 and 12, but not necessarily in this order. Then H.M., G.M. and A.M. respectively are
Options:
A) $ 15,\ 12,\ \frac{144}{15} $
B) $ \frac{144}{15},\ 12,\ 15 $
C) $ 12,\ 15,\ \frac{144}{15} $
D) $ \frac{144}{15},\ 15,\ 12 $
Show Answer
Answer:
Correct Answer: B
Solution:
As we know $ A.M.>G.M.>H.M. $
$ \therefore $ $ A.M.=15,\ G.M.=12,\ H.M.=\frac{144}{15} $ .
BETA
