[MP PET 1986]
A) $ e^{x} $
B) $ {e^{-x}} $
C) $ e $
D) $ {e^{x^{2}}} $
Correct Answer: B
$ 1-x+\frac{x^{2}}{2!}-\frac{x^{3}}{3!}+….\infty ={e^{-x}} $.
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