Sequence And Series Question 423
Question: The sum of 3 numbers in geometric progression is 38 and their product is 1728. The middle number is
[MP PET 1994]
Options:
A) 12
B) 8
C) 18
D) 6
Show Answer
Answer:
Correct Answer: A
Solution:
Let the three numbers be $ \frac{a}{r},\ a $ and $ ar $ , then $ a^{3}=1728 $
$ \Rightarrow $ $ a=12 $ Hence the middle term is 12.
BETA
