Sequence And Series Question 487

Question: The sum of all two digit numbers which, when divided by 4, yield unity as a remainder is

Options:

A) 1190

B) 1197

C) 1210

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

The given numbers are 13, 17, ….. 97. This is an AP with first term 13 and common difference 4. Let the number of terms be $ n $ . Then $ 97=13+(n-1)4 $
$ \Rightarrow $ $ 4n=88 $
$ \Rightarrow $ $ n=22 $ Therefore the sum of the numbers $ =\frac{22}{2}[13+97]=11(110)=1210 $ .