Sequence And Series Question 487
Question: The sum of all two digit numbers which, when divided by 4, yield unity as a remainder is
Options:
A) 1190
B) 1197
C) 1210
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
The given numbers are 13, 17, ….. 97. This is an AP with first term 13 and common difference 4. Let the number of terms be $ n $ . Then $ 97=13+(n-1)4 $
$ \Rightarrow $ $ 4n=88 $
$ \Rightarrow $ $ n=22 $ Therefore the sum of the numbers $ =\frac{22}{2}[13+97]=11(110)=1210 $ .