Sequence And Series Question 492
Question: If $ a,,b,,c,,d $ are positive real numbers such that $ a+b+c+d $ $ =2, $ then $ M=(a+b)(c+d) $ satisfies the relation
[IIT Screening 2000]
Options:
A) $ 0<M\le 1 $
B) $ 1\le M\le 2 $
C) $ 2\le M\le 3 $
D) $ 3\le M\le 4 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{(a+b)+(c+d)}{2}\ge \sqrt{(a+b)(c+d)} $ or $ \frac{2}{2}>\sqrt{M} $ or $ 1\ge M $ Also $ M>0.So,0<M\le 1 $ .
BETA
