Sequence And Series Question 496
Question: The sum of the first and third term of an arithmetic progression is 12 and the product of first and second term is 24, then first term is
[MP PET 2003]
Options:
A) 1
B) 8
C) 4
D) 6
Show Answer
Answer:
Correct Answer: C
Solution:
Let first 3 terms be $ a-d,a $ and $ a+d $ Now $ (a-d)+(a+d)=12 $
$ \Rightarrow $ $ 2a=12 $
$ \Rightarrow $ $ a=6 $ and $ (a-d)a=24 $
Þ $ 6(6-d)=24 $
Þ $ d=2 $ \ First term = $ a-d=6-2=4 $ .
BETA
