SATHEE: Sequence And Series Question 502

Sequence And Series Question 502

Question: $ 7^{th} $ term of an A.P. is 40, then the sum of first 13 terms is

[Karnataka CET 2003]

Options:

A) 53

B) 520

C) 1040

D) 2080

Show Answer

Answer:

Correct Answer: B

Solution:

$ 7^{th} $ term of an A.P. $ =40 $ $ a+6d=40 $ $ S_{13}=\frac{13}{2}[2a+(13-1)d]=\frac{13}{2}[2(a+6d)] $ $ =\frac{13}{2}\ .\ 2\ .\ 40=520 $ .

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Sequence And Series Question 502

Question: $ 7^{th} $ term of an A.P. is 40, then the sum of first 13 terms is

Options:

Answer:

Solution:

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