Sequence And Series Question 53
Question: $ \frac{e^{2}+1}{2,e}= $
Options:
A) $ 1+\frac{2}{2,!}+\frac{2^{2}}{3,!}+\frac{2^{3}}{4,!}+…..\infty $
B) $ 1+\frac{1}{2,!}+\frac{1}{4,!}+\frac{1}{6,!}+…..\infty $
C) $ \frac{1}{2}( 1+\frac{1}{2,!}+\frac{1}{4,!}+….\infty ) $
D) $ \frac{1}{2}( 1+\frac{1}{1,!}+\frac{1}{2,!}+\frac{1}{3,!}+….\infty ) $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{e^{2}+1}{2e}=\frac{e+{e^{-1}}}{2}=1+\frac{1}{2\ !,}+\frac{1}{4\ !}+\frac{1}{6\ !}+……\infty $
BETA
