Sequence And Series Question 576
Question: $ 7^{th} $ term of the sequence $ \sqrt{2},\ \sqrt{10},\ 5\sqrt{2},\ ……. $ is
Options:
A) $ 125\sqrt{10} $
B) $ 25\sqrt{2} $
C) 125
D) $ 125\sqrt{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
Given sequence is $ \sqrt{2},\ \sqrt{10},\ \sqrt{50}…….. $ Common ratio $ r=\sqrt{5} $ , first term $ a=\sqrt{2} $ , then $ 7^{th} $ term $ t_7=\sqrt{2}{{(\sqrt{5})}^{7-1}}=\sqrt{2}{{(\sqrt{5})}^{6}}=\sqrt{2}{{(5)}^{3}}=125\sqrt{2} $ .
BETA
