Sequence And Series Question 595
Question: The number of terms in the series $ 101+99+97+…..+47 $ is
Options:
A) 25
B) 28
C) 30
D) 20
Show Answer
Answer:
Correct Answer: B
Solution:
Given series $ 101+99+97+………+47 $ So, first term $ a=101 $ , common difference $ d=-2 $ and last term $ l=47 $ We know that last term of a series $ T_{l}=a+(n-1)d\Rightarrow 47=101+(n-1)(-2) $ $ -54=(n-1)(-2)\Rightarrow n=28 $ .
BETA
