Sequence And Series Question 606
Question: Fifth term of a G.P. is 2, then the product of its 9 terms is
[Pb. CET 1990, 94; AIEEE 2002]
Options:
A) 256
B) 512
C) 1024
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Let the 9 terms of a G.P. is $ \frac{a}{r^{4}},\frac{a}{r^{3}},\frac{a}{r^{2}},\frac{a}{r},a, $ $ ar,ar^{2},ar^{3},ar^{4} $ . Given, fifth term $ a=2 $ Hence product of 9 terms is $ a^{9}={{(2)}^{9}}=512 $ .
BETA
