Sequence And Series Question 637

Question: The product (32)(32) 1/6(32)1/36 …… to $ \infty $ is

[Kerala (Engg.) 2005]

Options:

A) 16

B) 32

C) 64

D) 0

E) 62

Show Answer

Answer:

Correct Answer: C

Solution:

(32)(32)1/6(32)1/36…… $ \infty $ = $ {{(32)}^{1+\frac{1}{6}+\frac{1}{36}+…..\infty }} $ $ ={{(32)}^{\frac{1}{1-(1/6)}}} $ $ ={{(32)}^{\frac{1}{5/6}}}={{(32)}^{6/5}} $ $ =2^{6}=64 $ .



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