Sequence-And-Series Question 668
Question: x and y are positive number. Let g and a be G. M. and AM of these numbers. Also let G be G.M. of x + 1 and y + 1. If G and g are roots of equation $ x^{2}-5x+6=0 $ , then
Options:
A) $ x=2,,y=\frac{3}{4} $
B) $ x=\frac{3}{4},y=12 $
C) $ x=\frac{5}{2},y=\frac{8}{5} $
D) $ x=y=2 $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] The roots of equation are 2 and 3
$ \therefore ,g=\sqrt{xy}=2\Rightarrow xy=4 $ $ G=\sqrt{(x+1)(y+1)}=3\Rightarrow (x+1)(y+1)=9 $
$ \therefore ,x=y=2 $
BETA
