Sequence And Series Question 9
Question: If sixth term of a H.P. is $ \frac{1}{61} $ and its tenth term is $ \frac{1}{105}, $ then first term of that H.P. is
[Karnataka CET 2001]
Options:
A) $ \frac{1}{28} $
B) $ \frac{1}{39} $
C) $ \frac{1}{6} $
D) $ \frac{1}{17} $
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Answer:
Correct Answer: C
Solution:
of H.P. $ =\frac{1}{61},\Rightarrow T_6 $ of A.P. = 61 and of H.P. $ =\frac{1}{105}\Rightarrow ,T_{10} $ of A.P. = 105, so $ a+5d=61 $ …….(i) and $ a+9d=105 $ ?..(ii) From (i) and (ii), $ a=6 $ Therefore first term of H.P. $ =\frac{1}{a}=\frac{1}{6} $ .