Statistics And Probability Question 142
Question: Three digits are chosen at random from 1, 2, 3, 4, 5, 6, 7, 8 and 9 without repeating any digit. What is the probability that the product is odd?
Options:
A) $ \frac{2}{3} $
B) $ \frac{7}{48} $
C) $ \frac{5}{42} $
D) $ \frac{5}{108} $
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Answer:
Correct Answer: C
Solution:
- [c] Total no. of 3-digit numbers $ =9\times 8\times 7=504 $ For product to be odd, we have to choose only from odd numbers.
$ \therefore $ Total no. of 3-digit no, whose product are odd $ =5\times 4\times 3=60 $
$ \therefore $ Required probability $ =\frac{60}{504}=\frac{5}{42} $
BETA
