[AMU 1993; DCE 1998]
A) 0
B) 1.2
C) 5
D) 25
Correct Answer: B
A.M. = $ \frac{3+4+5+6+7}{5}=5 $ \ Mean deviation $ =\frac{\Sigma |x_{i}-\bar{x}|}{n} $ $ =\frac{|3-5|+|4-5|+|5-5|+|6-5|+|7-5|}{5} $ $ =\frac{2+1+0+1+2}{5} $ $ =\frac{6}{5}=1.2 $ .
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