Statistics And Probability Question 163

Question: Let A and B be two events. Then $ 1+P(A\cap B)-P(B)-P(A) $ is equal to

Options:

A) $ P(\bar{A}\cup \bar{B}) $

B) $ P(A\cap \bar{B}) $

C) $ P(\bar{A}\cap B) $

D) $ P(\bar{A}\cap \bar{B}) $

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Answer:

Correct Answer: D

Solution:

  • [d] we know $ P(A\cup B)=P(A)+P(B)-P(A\cap B) $ Consider; $ 1+P(A\cap B)-P(B)-P(A) $ $ =-1-P(B)-P(A)+P(A)+P(B)-P(A\cup B) $ $ =1-P(A\cup B) $