Statistics And Probability Question 168

Question: The probabilities of three mutually exclusive events are 2/3, 1/4 and 1/6. The statement is

[MNR 1987; UPSEAT 2000]

Options:

A) True

B) Wrong

C) Could be either

D) Do not know

Show Answer

Answer:

Correct Answer: B

Solution:

  •                 Since here                                                                             $ P(A+B+C)=P(A)+P(B)+P(C) $                                                                           $ =\frac{2}{3}+\frac{1}{4}+\frac{1}{6}=\frac{13}{12} $  , which is greater than 1.                                 Hence the statement is wrong.