Statistics And Probability Question 172
Three numbers are chosen at random without replacement from the set $ A={x|1\le x\le 10,x\in N} $ . The probability that the minimum of the chosen numbers is 3 and maximum is 7, is
Options:
A) $ \frac{1}{12} $
B) $ \frac{1}{15} $
C) $ \frac{1}{40} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- [c] $ n(S){{=}^{10}}C_3 $ and $ n(E){{=}^{3}}C_1, $ becomes on selecting $ 3,7 $ and we have to select one from 4, 5 and 6.
$ \therefore P(E)=\frac{^{3}C_1}{^{10}C_3}=\frac{1}{40}. $
BETA
