Statistics And Probability Question 198
Question: If Mohan has 3 tickets of a lottery containing 3 prizes and 9 blanks, then his chance of winning prize are
Options:
A) $ \frac{34}{55} $
B) $ \frac{21}{55} $
C) $ \frac{17}{55} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
-
Mohan can gets one prize, 2 prizes or 3 prizes and his chance of failure means he get no prize. Number of total ways $ ={}^{12}C_3=220 $ Favourable number of ways to be failure $ ={}^{9}C_3=84 $ Hence required probability $ =1-\frac{84}{220}=\frac{34}{55}. $
BETA
