Statistics And Probability Question 201

Question: Suppose that A, B, C are events such that $ P,(A)=P,(B)=P,(C)=\frac{1}{4},,P,(AB)=P,(CB)=0,,P,(AC)=\frac{1}{8}, $ then $ P,(A+B)= $

[MP PET 1992]

Options:

A) 0.125

B) 0.25

C) 0.375

D) 0.5

Show Answer

Answer:

Correct Answer: D

Solution:

  •                                                                                             $ P(A+B)=P(A)+P(B)-P(AB) $                                                                    $ =\frac{1}{4}+\frac{1}{4}-0=\frac{1}{2}. $