Statistics And Probability Question 201
Question: Suppose that A, B, C are events such that $ P,(A)=P,(B)=P,(C)=\frac{1}{4},,P,(AB)=P,(CB)=0,,P,(AC)=\frac{1}{8}, $ then $ P,(A+B)= $
[MP PET 1992]
Options:
A) 0.125
B) 0.25
C) 0.375
D) 0.5
Show Answer
Answer:
Correct Answer: D
Solution:
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$ P(A+B)=P(A)+P(B)-P(AB) $ $ =\frac{1}{4}+\frac{1}{4}-0=\frac{1}{2}. $