[IIT 1989]
A) 0.5
B) 0.44
C) 0.6
D) None of these
Correct Answer: B
Here $ P(X)=0.3; $ $ P(Y)=0.2 $ Now $ P(X\cup Y)=P(X)+P(Y)-P(X\cap Y) $ Since these are independent events, so $ P(X\cap Y)=P(X)\,.\,P(Y) $ Thus required probability $ =0.3+0.2-0.06=0.44 $ .
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