Statistics And Probability Question 344

Question: If the mean of the numbers $ 27+x,31+x,89+x,107+x,156+x $ is 82, then the mean of $ 130+x $ , $ 126+x,68+x,50+x,1+x $

Options:

A) 75

B) 157

C) 82

D) 80

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Given $ 82=\frac{(27+x)+(31+x)+(89+x)+(107+x)+(156+x)}{5} $
$ \Rightarrow 82\times 5=410+5x\Rightarrow 410-410=5x\Rightarrow x=0 $
$ \therefore $ Required mean is, $ \bar{x}=\frac{130+x+126+x+68+x+50+x+1+x}{5} $ $ \bar{x}=\frac{375+5x}{5}=\frac{375+0}{5}=\frac{375}{5}=75 $



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