Statistics And Probability Question 40

Question: A father has 3 children with at least one boy. The probability that he has 2 boys and 1 girl is

Options:

A) $ 1/4 $

B) $ 1/3 $

C) $ 2/3 $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • [b] Consider the following events: A: Father has at least one boy B: Father has 2 boys and one girl Then, A=one boy and 2 girls, 2 boys and one girl, 3 boys and no girl $ A\cap B=2 $ boys and one girl now, the required probability is $ P(A/B)=\frac{P(A\cap B)}{P(A)}=\frac{1}{3}. $