Statistics And Probability Question 407
Question: The arithmetic mean of numbers a, b, c, d, e, is M. What is the value of $ (a-M)+(b-M)+(c-M)+(d-M)+(e-M)? $
Options:
A) M
B) $ a+b+c+d+e $
C) 0
D) 5 M
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Given $ M=\frac{a+b+c+d+e}{5} $
$ \Rightarrow a+b+c+d+e=5M $
$ \Rightarrow a+b+c+d+e-5M=0 $
$ \Rightarrow (a-M)+(b-M)+(c-M) $ $ +(d-M)+(e-M)=0 $ Hence, required value = 0
BETA
