Statistics And Probability Question 446

Question: If A and B are two events such that $ P,(A\cup B),+P,(A\cap B)=\frac{7}{8} $ and $ P,(A)=2,P,(B), $ then $ P,(A)= $

Options:

A) $ \frac{7}{12} $

B) $ \frac{7}{24} $

C) $ \frac{5}{12} $

D) $ \frac{17}{24} $

Show Answer

Answer:

Correct Answer: A

Solution:

  •                 Since we have             $ P(A\cup B)+P(A\cap B)=P(A)+P(B) $  $ =P(A)+\frac{P(A)}{2} $                                   
    

$ \Rightarrow \frac{7}{8}=\frac{3P(A)}{2}\Rightarrow P(A)=\frac{7}{12}. $