Statistics And Probability Question 51

Question: Let A and B be two events such that $ P(A\cap B’)=0.20,P(A’\cap B)=0.15, $ $ P(A’\cap B’)=0.1, $ Then $ P(A/B) $ is equal to

Options:

A) 11/14

B) 2/11

C) 2/7

D) 1/7

Show Answer

Answer:

Correct Answer: A

Solution:

  • [a] $ P(A\cap B’)=P(A)-P(A\cap B)=0.20 $ Also, $ P(A’\cap B)=P(B)-P(A\cap B)=0.15 $
    $ \Rightarrow P(A)+P(B)-2P(A-B)=0.35 $ Now, $ P(A’\cap B’)=1-P(A\cup B) $
    $ \Rightarrow 0.1=1-P(A)-P(B)+P(A\cap B) $
    $ \Rightarrow P(A)+P(B)-P(A\cap B)=0.9 $
    $ \Rightarrow P(A\cap B)=0.9-0.35=0.55 $ and $ P(A)=0.75,P(B)=0.70 $ Now, $ P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0.55}{0.70} $