Statistics And Probability Question 537
Question: The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then $ P(X=1) $ is
[AIEEE 2003]
Options:
A) 1/32
B) 1/16
C) 1/8
D) ¼
Show Answer
Answer:
Correct Answer: A
Solution:
-
$ . \begin{matrix} np=4 \\\ npq=2 \\\ \end{matrix} \}\,\Rightarrow \,q=\frac{1}{2},\,p=\frac{1}{2},\,n=8 $ $ P\,(X=1)={{\,}^{8}}C_1( \frac{1}{2} )\,{{( \frac{1}{2} )}^{7}} $ $ =8.\,\frac{1}{2^{8}}=\frac{1}{2^{5}}=\frac{1}{32} $ .
BETA
