Statistics And Probability Question 576
Question: If A and B are arbitrary events, then
[DCE 2002]
Options:
A) $ P(A\cap B)\ge P(A)+P(B) $
B) $ P(A\cup B)\le P(A)+P(B) $
C) $ P(A\cap B)=P(A)+P(B) $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
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$ P(A\cup B)=P(A)+P(B)-P(A\cap B)\le P(A)+P(B) $ , $ (\because P(A\cap \,B)\ge \,0) $ .