[EAMCET 2003]
A) 0.3
B) 0.5
C) 0.7
D) 0.9
Correct Answer: D
$ P(A'\,\cap B')\,=1-P(A\cup B)\,=1-0.8=0.2 $ $ P(A'\cup B')=1-P(A\cap B)=1-0.3=0.7 $ $ P(A'\cup B')=P(A')\,+\,P(B')-P(A'\cap B') $
Þ $ ,0.7,=P(A’)+P(B’)-0.2 $
Þ
$ \therefore $ .
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