Statistics-And-Probability Question 591

Question: Suppose a population A has 100 observations $ 101,102,…..,200 $ and another population B has 100 observations 151, 152 ???? 250. If $ V_{A}andV_{B} $ represent the variances of the two populations, respectively then $ \frac{V_{A}}{V_{B}} $ is

Options:

A) 1

B) $ \frac{9}{4} $

C) $ \frac{4}{9} $

D) $ \frac{2}{3} $

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Answer:

Correct Answer: A

Solution:

[a] $ \sigma _x^{2}=\frac{\sum{d _i^{2}}}{n} $

(Here deviations are taken from the mean). Since A and B both have 100 consecutive integers, therefore both have same standard deviation and hence the variance.

$ \therefore \frac{V_{A}}{V_{B}}=1 $

(As $ \sum{d_i^{2}} $ is same in both the cases)