Statistics-And-Probability Question 595
Question: For the data 3, 5, 1, 6, 5, 9, 2, 8, 6 the mean, median and mode are x, y, and z respectively. Which one of the following is correct?
Options:
A) $ x=y\ne z $
B) $ x\ne y=z $
C) $ x\ne y\ne z $
D) $ x=y=z $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Given data $ 3,,5,1,6,9,5,2,8,6 $ and mean, median and mode are x, y, z respectively. Rearranging data $ 1,2,3,5,5,5,6,6,8,9 $ Mean $ =x $ $ =\frac{1+2+3+5+5+5+6+6+8+9}{10}=\frac{50}{10}=5 $ Median $ =y=\frac{\frac{n^{th}}{2}term+{{( \frac{n}{2}+1 )}^{th}}term}{2} $ $ y=\frac{5+5}{2}=5 $ Mode (z) = most frequently occurring value =5 Hence $ x=y=z. $
BETA
