Statistics-And-Probability Question 606
Question: If the mean of the numbers $ 27+x,31+x,89+x,107+x,156+x $ is 82, then the mean of $ 130+x $ , $ 126+x,68+x,50+x,1+x $
Options:
A) 75
B) 157
C) 82
D) 80
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Given $ 82=\frac{(27+x)+(31+x)+(89+x)+(107+x)+(156+x)}{5} $
$ \Rightarrow 82\times 5=410+5x\Rightarrow 410-410=5x\Rightarrow x=0 $
$ \therefore $ Required mean is, $ \bar{x}=\frac{130+x+126+x+68+x+50+x+1+x}{5} $ $ \bar{x}=\frac{375+5x}{5}=\frac{375+0}{5}=\frac{375}{5}=75 $
BETA
