Straight Line Question 10

Question: If $ \frac{1}{a{b}’}+\frac{1}{b{a}’}=0, $ then lines $ \frac{x}{a}+\frac{y}{b}=1 $ and $ \frac{x}{{{b}’}}+\frac{y}{{{a}’}}=1 $ are [MP PET 1984]

Options:

A) Parallel

B) Inclined at $ 60^{o} $ to each other

C) Perpendicular to each other

D) Inclined at $ 30^{o} $ to each other

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ a_1a_2+b_1b_2=\frac{1}{a{b}’}+\frac{1}{{a}‘b}=0 $ Therefore, the lines are perpendicular.